Optimal. Leaf size=218 \[ \frac {2 (4 A-i B) \tan (e+f x)}{15 a^2 c f \sqrt {a+i a \tan (e+f x)} \sqrt {c-i c \tan (e+f x)}}+\frac {-B-i A}{3 f (a+i a \tan (e+f x))^{5/2} (c-i c \tan (e+f x))^{3/2}}+\frac {B+4 i A}{15 a c f (a+i a \tan (e+f x))^{3/2} \sqrt {c-i c \tan (e+f x)}}+\frac {B+4 i A}{15 c f (a+i a \tan (e+f x))^{5/2} \sqrt {c-i c \tan (e+f x)}} \]
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Rubi [A] time = 0.29, antiderivative size = 216, normalized size of antiderivative = 0.99, number of steps used = 5, number of rules used = 4, integrand size = 45, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.089, Rules used = {3588, 78, 45, 39} \[ \frac {2 (4 A-i B) \tan (e+f x)}{15 a^2 c f \sqrt {a+i a \tan (e+f x)} \sqrt {c-i c \tan (e+f x)}}-\frac {B+i A}{3 f (a+i a \tan (e+f x))^{5/2} (c-i c \tan (e+f x))^{3/2}}+\frac {B+4 i A}{15 a c f (a+i a \tan (e+f x))^{3/2} \sqrt {c-i c \tan (e+f x)}}+\frac {B+4 i A}{15 c f (a+i a \tan (e+f x))^{5/2} \sqrt {c-i c \tan (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 39
Rule 45
Rule 78
Rule 3588
Rubi steps
\begin {align*} \int \frac {A+B \tan (e+f x)}{(a+i a \tan (e+f x))^{5/2} (c-i c \tan (e+f x))^{3/2}} \, dx &=\frac {(a c) \operatorname {Subst}\left (\int \frac {A+B x}{(a+i a x)^{7/2} (c-i c x)^{5/2}} \, dx,x,\tan (e+f x)\right )}{f}\\ &=-\frac {i A+B}{3 f (a+i a \tan (e+f x))^{5/2} (c-i c \tan (e+f x))^{3/2}}+\frac {(a (4 A-i B)) \operatorname {Subst}\left (\int \frac {1}{(a+i a x)^{7/2} (c-i c x)^{3/2}} \, dx,x,\tan (e+f x)\right )}{3 f}\\ &=-\frac {i A+B}{3 f (a+i a \tan (e+f x))^{5/2} (c-i c \tan (e+f x))^{3/2}}+\frac {4 i A+B}{15 c f (a+i a \tan (e+f x))^{5/2} \sqrt {c-i c \tan (e+f x)}}+\frac {(4 A-i B) \operatorname {Subst}\left (\int \frac {1}{(a+i a x)^{5/2} (c-i c x)^{3/2}} \, dx,x,\tan (e+f x)\right )}{5 f}\\ &=-\frac {i A+B}{3 f (a+i a \tan (e+f x))^{5/2} (c-i c \tan (e+f x))^{3/2}}+\frac {4 i A+B}{15 c f (a+i a \tan (e+f x))^{5/2} \sqrt {c-i c \tan (e+f x)}}+\frac {4 i A+B}{15 a c f (a+i a \tan (e+f x))^{3/2} \sqrt {c-i c \tan (e+f x)}}+\frac {(2 (4 A-i B)) \operatorname {Subst}\left (\int \frac {1}{(a+i a x)^{3/2} (c-i c x)^{3/2}} \, dx,x,\tan (e+f x)\right )}{15 a f}\\ &=-\frac {i A+B}{3 f (a+i a \tan (e+f x))^{5/2} (c-i c \tan (e+f x))^{3/2}}+\frac {4 i A+B}{15 c f (a+i a \tan (e+f x))^{5/2} \sqrt {c-i c \tan (e+f x)}}+\frac {4 i A+B}{15 a c f (a+i a \tan (e+f x))^{3/2} \sqrt {c-i c \tan (e+f x)}}+\frac {2 (4 A-i B) \tan (e+f x)}{15 a^2 c f \sqrt {a+i a \tan (e+f x)} \sqrt {c-i c \tan (e+f x)}}\\ \end {align*}
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Mathematica [A] time = 11.83, size = 133, normalized size = 0.61 \[ -\frac {i \sqrt {c-i c \tan (e+f x)} (20 (A-i B) \cos (2 (e+f x))+(A-4 i B) \cos (4 (e+f x))+40 i A \sin (2 (e+f x))+4 i A \sin (4 (e+f x))-45 A+10 B \sin (2 (e+f x))+B \sin (4 (e+f x)))}{120 a^2 c^2 f \sqrt {a+i a \tan (e+f x)}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.92, size = 180, normalized size = 0.83 \[ \frac {{\left ({\left (-5 i \, A - 5 \, B\right )} e^{\left (10 i \, f x + 10 i \, e\right )} + {\left (-65 i \, A - 35 \, B\right )} e^{\left (8 i \, f x + 8 i \, e\right )} + {\left (-48 i \, A + 48 \, B\right )} e^{\left (7 i \, f x + 7 i \, e\right )} + {\left (30 i \, A - 30 \, B\right )} e^{\left (6 i \, f x + 6 i \, e\right )} + {\left (-48 i \, A + 48 \, B\right )} e^{\left (5 i \, f x + 5 i \, e\right )} + {\left (110 i \, A - 10 \, B\right )} e^{\left (4 i \, f x + 4 i \, e\right )} + {\left (23 i \, A - 13 \, B\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + 3 i \, A - 3 \, B\right )} \sqrt {\frac {a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} e^{\left (-5 i \, f x - 5 i \, e\right )}}{240 \, a^{3} c^{2} f} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {B \tan \left (f x + e\right ) + A}{{\left (i \, a \tan \left (f x + e\right ) + a\right )}^{\frac {5}{2}} {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.36, size = 199, normalized size = 0.91 \[ -\frac {i \sqrt {a \left (1+i \tan \left (f x +e \right )\right )}\, \sqrt {-c \left (-1+i \tan \left (f x +e \right )\right )}\, \left (8 i A \left (\tan ^{6}\left (f x +e \right )\right )-2 i B \left (\tan ^{5}\left (f x +e \right )\right )+2 B \left (\tan ^{6}\left (f x +e \right )\right )+20 i A \left (\tan ^{4}\left (f x +e \right )\right )+8 A \left (\tan ^{5}\left (f x +e \right )\right )-5 i B \left (\tan ^{3}\left (f x +e \right )\right )+5 B \left (\tan ^{4}\left (f x +e \right )\right )+15 i A \left (\tan ^{2}\left (f x +e \right )\right )+20 A \left (\tan ^{3}\left (f x +e \right )\right )-3 i B \tan \left (f x +e \right )+3 i A +12 A \tan \left (f x +e \right )-3 B \right )}{15 f \,c^{2} a^{3} \left (\tan \left (f x +e \right )+i\right )^{3} \left (-\tan \left (f x +e \right )+i\right )^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 10.64, size = 249, normalized size = 1.14 \[ \frac {\sqrt {\frac {a\,\left (\cos \left (2\,e+2\,f\,x\right )+1+\sin \left (2\,e+2\,f\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,e+2\,f\,x\right )+1}}\,\left (95\,A\,\sin \left (2\,e+2\,f\,x\right )-30\,B+A\,\cos \left (2\,e+2\,f\,x\right )\,85{}\mathrm {i}+A\,\cos \left (4\,e+4\,f\,x\right )\,20{}\mathrm {i}+A\,\cos \left (6\,e+6\,f\,x\right )\,3{}\mathrm {i}-5\,B\,\cos \left (2\,e+2\,f\,x\right )-10\,B\,\cos \left (4\,e+4\,f\,x\right )-3\,B\,\cos \left (6\,e+6\,f\,x\right )-A\,60{}\mathrm {i}+20\,A\,\sin \left (4\,e+4\,f\,x\right )+3\,A\,\sin \left (6\,e+6\,f\,x\right )-B\,\sin \left (2\,e+2\,f\,x\right )\,5{}\mathrm {i}+B\,\sin \left (4\,e+4\,f\,x\right )\,10{}\mathrm {i}+B\,\sin \left (6\,e+6\,f\,x\right )\,3{}\mathrm {i}\right )}{240\,a^3\,c\,f\,\sqrt {\frac {c\,\left (\cos \left (2\,e+2\,f\,x\right )+1-\sin \left (2\,e+2\,f\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,e+2\,f\,x\right )+1}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {A + B \tan {\left (e + f x \right )}}{\left (i a \left (\tan {\left (e + f x \right )} - i\right )\right )^{\frac {5}{2}} \left (- i c \left (\tan {\left (e + f x \right )} + i\right )\right )^{\frac {3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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